Matematika Sekolah Menengah Atas Q.panjang = 8 dmlebar = 0,000000007 kmtinggi = 10 cmjari : 21 cmditanya :gabungan volume balok dan tabung ? ( dalam satuan cm )note :nih gambar nya ya nanaz <3​

pedrogislasonulv – March 07, 2023

Q.
panjang = 8 dm
lebar = 0,000000007 km
tinggi = 10 cm
jari : 21 cm

ditanya :
gabungan volume balok dan tabung ? ( dalam satuan cm )

note :
nih gambar nya ya nanaz <3
​

Penjelasan dengan langkah-langkah:

p = 8 dm = 800 mm

l = 0,000000007 x 1.000.000 mm = 7/1.000 mm

t = 10 cm = 100 mm

r = 21 cm

V = plt + πr²t

V = (800 x 7/1.000 x 100) mm³ + (22/7 x 21² x 10) cm³

V = 560 mm³ + 13.860 cm³

V = (560/1.000) cm³ + 13.860 cm³

V = 0,56 + 13.860

V = 13.860,56 cm³

Jawaban:

8 dm = 8 × 10 = 80 cm

0,000000007 km = 0,000000007 × 100.000 = 0,00007 Cm

10 cm = 10 cm

21 cm = 21 cm

Volume balok

= p × l × t

= 80 × 0,00007 × 10

= 0,056 × 10

= 0,56 Cm³

Volume tabung

= phi × r × r × t

= 22/7 × 21 × 21 × 10

= 22 × 3 × 21 × 10

= 66 × 21 × 10

= 1.386 × 10

= 13.860 Cm³

Volume gabungan

= volume balok + volume tabung

= 0,56 + 13.860

= 13.860,56 Cm³

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